Oh yeah, the answer to the calculus question, sin(sin(sin(x))), is cos(sin(sin(x))cos(sin(x))cos x. Basically, the analysis of this problem is a multiple chain rule. You take the derivative of the outermost equation first and you carry over the rest of the equation. Since the derivative of sine is cosine, I took the derivative of the outermost sine first and carried the two sines over. You repeat the process with the second sine in the parenthesis, and then the third sine. This problem really was not that bad. I could have posted one with a bunch of square roots, since square roots are fractional exponents. Those problems can be rather painful at times. Or for that matter, any exponential derivatives are painful, except for e^x, since the derivative of e^x is itself. So, anywho, I know I am boring you all to death. I can see your eyes rolling. In that case, I will stop. :)
Anyways, after my test tomorrow, I will be posting a couple posts on God's power being made perfect in our weaknesses through the eyes of real life examples. Could one of them be myself? What is my weakness? The other is another blogger, who has experienced many things in her life this past year. She is a true warrior. How is she and the other person overcoming? Tune in tomorrow.....
Sola Deo Gloria!!!!